/*
Summary: Print sum of series
1 + 1/2 + 1/3 + 1/4 + ... + 1/N.
*/
#include<stdio.h>
#include<conio.h>
int main()
{
double n,sum=0,i;
printf("\n Please Give The Value of N: ");
scanf("%lf",&n);
for(i=1;i<=n;i++)
{
sum = sum + (1/i);
if(i==1)
printf("\n 1 +");
else if(i==n)
printf(" (1/%.0lf) ",i);
else
printf(" (1/%.0lf) + ",i);
}
printf("\n\n THE SUM OF THIS SERIES IS %.2lf",sum);
return 0;
}
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